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If the average length of a double helix in human chromosome is 3.9 cm, approximately how many base pairs are present in such chromosome?

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Answer:

The average length of a double helix in human chromosome whose length is 3.9 cm has approximately 114.7 million base pairs

Step-by-step explanation:

Lenght of DNA = number of base pairs * distance between consecutive base pairs

The distance between two consecutive base pairs bonded by hydrogen bonds is 0.34 nm.

If the average length of a double helix DNA molecule in human chromosome is 3.9 cm, the average number of base can then be calculated using the formula below:

Average number of base pairs = length of DNA ÷ distance between consecutive base pairs

Average number of base pairs = 3.9 cm/ 0.34 nm = 0.039 m/ 0.00000000034 m

Average number of base pairs = 114705882.4

Therefore, the average length of a double helix in human chromosome whose length is 3.9 cm has approximately 114.7 million base pairs

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