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Suppose m is the line with equation y = −4 and ΔA'B'C is mapped to ΔA"B"C" by applying the glide reflection T⟨3, 0⟩ ∘ Rm. What are the coordinates of ΔA″B″C″?

User Yerke
by
5.5k points

1 Answer

0 votes

Answer:


A
B
C

Step-by-step explanation:

Given

See attachment for graph


A' = (-4, -5)


B'=(-5, -2)


C' = (-2, -1)

First, reflect over
y =-4

The rule is:
(x,y) ==> (x,y+h)

Where
h =-4

So:


A' = (-4, -5)
==>
A'' = (-4, 1-4) = (-4, -3)\\


B'=(-5, -2)
==>
B'' = (-5, -2-4) = (-5, -6)


C' = (-2, -1)
==>
C'' = (-2, -3-4) = (-2, -7)

So, we have:


A
B
C

Next translate A''B''C'' by T(3, 0), we have;

The rule is:
(x,y)==>(x+3,y+0)


A
==>
A


B
==>
B


C
==>
C

Hence, A''B''C'' are:


A
B
C

Suppose m is the line with equation y = −4 and ΔA'B'C is mapped to ΔA"B&quot-example-1
User Sshroff
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4.9k points