Question

A rocket is launched from a hill, the hill is 80 ft high and the rocket has a velocity of 64 ft/s what is the maximum height of the rocket and when will it reach that height?

Answer 1

Answer:143.60 ft

Explanation:

Given

Height of hill
`h=80\ ft`

the launch velocity of the rocket is
`u=64\ ft/s`

At maximum height, the velocity of the rocket is zero

using the third equation of motion
`v^2-u^2=2as`

`\Rightarrow 0^2-64^2=2* (-32.2)* s\\\Rightarrow s=(64^2)/(64.4)=63.60\ ft`

The maximum height will be
`80+63.60=143.60\ ft`