Question

How to prove this using trig identities?

(Tan B + Cot B)^2 = sec^2B + csc^2B

Thanks and please shows steps. I will vote best answer and helpful and do more.

Answer 1

Explanation:

tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)

= (sin2B + cos2B)/[(cosB)(sinB)]

= 1/[(cosB)(sinB)]

= (1/cosB)(1/sinB)

= (secB)(cscB)