Answer:
interval is; ( 0.3881 to 0.6119 )
Option d) 0.3881 to 0.6119 is the correct answer
Explanation:
Given the data in the question;
n = 54
x = 27
p" = x/n = 27/54 = 0.5
90% confidence interval estimate for the proportion of undergraduates who plan to attend graduate school will be;
P" ±
× √(p"(1-P')/n)
we substitute
0.5 ±
× √(0.5(1-0.5)/54)
0.5 ± 1.644859 × 0.06804
so
Upper Limit = 0.5 + 1.644859 × 0.06804 = 0.6119
Lower Limit = 0.5 - 1.644859 × 0.06804 = 0.3881
Therefore interval is; ( 0.3881 to 0.6119 )
Option d) 0.3881 to 0.6119 is the correct answer