Answer:
(n + 1)(5m + 4)
Explanation:
Given
5mn + 5m + 4n + 4 ( factor the first/second terms and the third/fourth terms )
= 5m(n + 1) + 4(n + 1) ← factor out (n + 1) from each term
= (n + 1)(5m + 4)
(n + 1) (5m + 4)
⇒ (n + 1) (5m + 4)
⇒ 5mn + 4n + 5m + 4
⇒ 5mn + 5m + 4n + 4
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