Question

Find the polar angle (in radians with respect to +x-axis) of −3i + j.

Answer 1

`-18.43^(\circ)`

Step-by-step explanation:

Let
`\theta` be the polar angle of −3i + j. We can find it using the formula as follows :

`\tan\theta=(y)/(x)\\\\\tan\theta=(1)/(-3)\\\\\theta=\tan^(-1)((1)/(-3))\\\\\theta=-18.43^(\circ)`

So, the required polar angle is
`-18.43^(\circ)`.