Question

The heat of vaporization of water is 40.66 kJ/mol. How much heat is absorbed when 2.23 g of water boils at atmospheric pressure?

Answer 1

5.0kj

Step-by-step explanation:

1mole of H2O —>40.66kj

1mole of H2O—>18g

18g of H2O—>40.66K

2.23g. —>?

2.23g×40.66kj=90.6718g/kj

90.6718g/kj÷18g

=5.0kj