Question

A stationary 2 kg football is kicked by a footballer, the football moves off with a velocity of 5 m/s. If the footballer is in contact with the football for 0.5 s, what is the average force applied by the footballer

on the football?
Please helppp!!!!

Answer 1

F=20

Step-by-step explanation:

f=20

Answer 2

F = 20 N

Step-by-step explanation:

Given that,

Mass of the football, m = 2 kg

Initial speed, u = 0

Final speed,v = 5 m/s

The time of contact, t = 0.5 s

We need to found the average force applied by the footballer on the football. We can find it using the formula.

`F=(m(v-u))/(t)\\\\F=(2* (5-0))/(0.5)\\\\F=20\ N`

So, the required force is 20 N.