Question

1.3. If the surface tension coefficient of a fluid is 0,07 N/m and the radius

of the droplet is 2,5 mm. calculate:
1.3.1 surface tension force
(2)
1.3.2 difference in pressure of the droplet
(1)​

Answer 1

A) F = 0.011 N

B) ΔP = 5.6 N/m²

Step-by-step explanation:

We are given;

surface tension coefficient; S = 0.07 N/m

Radius; r = 2.5 mm = 0.025 m

A) Formula to find the surface tension force(F) is given by;

F = SL

Where L is effective length = 2πr

F = 0.07 × 2π × 0.025

F = 0.011 N

B) Formula for difference in pressure droplet is;

ΔP = 2S/r

Thus;

ΔP = (2 × 0.07)/0.025

ΔP = 5.6 N/m²