Question

Solve each equation in the real number system
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Answer 1

Explanation:

`- x {}^(3 ) - {x}^(2) + x + 1`

`- {x}^(2) ( x + 1) + 1(x + 1)`

`(1 - {x}^(2) )(x + 1) = 0`

`(1 - x)(1 + x)(x + 1) = 0`

`1- x = 0`

`x = 1`

`1 + x = 0`

`x = - 1`

`x = - 1`

So we have the answer of

-1 and 1.