Answer:
1. 105˚
2. 18
3. 7.79
Explanation:
1. Alternate interior angles are the same (Within this shape)
∠ACD = 40˚
Sum of angles in any triangle = 180˚
∠D = 180˚ - 40˚ - 35˚ = 105˚
2. Perimeter of ABCD
Find ∠B (Equilateral triangle of BC=CP=BP=4) ≅60˚
4+1 = CD = BA
CD+BA = 10
4 = BC=AD
BA+AD+DC+CB = 5+5+4+4 = 18
3. Find BN
AB = DC = 6
AD = BC = 9
∠ cos 30 = BN / 9
∠ cos 30 * 9 = BN
BN ≈ 7.79