Question

Ajar contains $36.25 in dimes (10 cents) and quarters (25 cents). There are 250

coins in the jar. How many quarters are there in the jar?

Answer 1

Step-by-step explanation:

The jar contains 2 types of coins dimes and quarters

the total amount is equal to 36.25 dollars

the total number of coins is 250

let number of dimes be x and quarters be y

let us put the equation

0.10x + 0.25y = 36.25

for our convinience convert all money to cents i.e. = 3625 cents

now the equations are

10x + 25y = 3625

x + y = 250

we need to solve for y i.e. number of quaters

y = 250 - x

rewrite the equation substituting y in x place

10(250 - y) +25 y = 3625

2500 - 10y +25y = 3625

15y = 1125

y = 75

so the number of quarters = 75

cross checking :

number of dimes = 250 - 75 = 175

total = 10x175 + 25x75 = 1750 + 1875 = 3625 = $36.25