Answer:
a. 7.53 ft high
b. 33.46 ft distance
Explanation:
a.
The vertex of the quadratic is located at ...
x = -b/(2a) = -(0.9)/(2(-0.0269)) ≈ 16.7286 . . . . feet from the start
The height at that point is ...
y = (16.7286)(-0.0269·16.7286 +0.9) ≈ 7.52788 ft
The gray kangaroo can jump about 7.53 ft high.
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b.
The height is zero when ...
0 = x(-0.0269x +0.9)
x = 0
x = 0.9/0.0269 ≈ 33.4572 . . . ft
The kangaroo can jump about 33.46 feet.