Answer:
Step-by-step explanation:
a. Since both the parents are carriers, they have one allele that is the gene for the normal trait and one gene that is for the sickle cell trait. So the genotypes of the parents are Hh
b. If we use a punnett square:
H h
H HH Hh
h Hh hh
Genotypic ratio: 1 HH: 2Hh: 1hh
Phenotypic ratio: 1 normal blood cell: 2 sickle cell carriers: 1 sickle cell disease