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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot. Show work. y=-16x^2+200x+82

2 Answers

3 votes

Answer:

Explanation:

y=-16x^2+200x+82

User Mustafa Shabib
by
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3 votes

Answer:

my answer is 707

Explanation:

Delta math told me lol

User Aarelovich
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