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What is the molarity of a solution with a 10.0 g AgNO3 dissolved in 0.5 L of solution ?

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Convert grams of silver nitrate to moles using the molar mass of AgNO3.

10.0 g AgNO3 • 1 mol AgNO3 / 169.87 g AgNO3 = 0.0589 mol AgNO3

Molarity is mol/L so divide the moles of AgNO3 by liters of solution.

0.0589 mol AgNO3 / 0.5 L = 0.118 M AgNO3
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