Question

One integer is 6 more than another. their product is 216. find the integers.

Answer 1

-18 and -12

Or, 18 and 12

Explanation:

Let the integers be 'a' & 'a + 6'.

Their product = 216

=> a x (a + 6) = 216

=> a² + 6a = 216

=> a² + 6a - 216 = 0

=> a² + (18 - 12)a - 216 = 0

=> a² + 18a - 12a - 216 = 0

=> a(a + 18) - 12(a + 18) = 0

=> (a + 18)(a - 12) = 0

=> a = - 18 or a = 12

Integers are: -18 and -18+6 = -12

Or, 12 and 12 + 6 = 18