Question

A stone is thrown at 45 degree with velocity 10m/sec.calculate the range of projectile​

Answer 1

As per Given Information

Angle on which the stone thrown ,theta = 45°

Velocity ,u = 10m/s

Acceleration due to gravity ,g is 10m/s²

We have to find the "Range of Projectile "

Range of projectile is denoted by R .

Using Formulae

`\\ \bigstar{\boxed{\pink{\bf{R = \frac{ {u}^(2)sin2 \theta }{g} }}}} \\ \\`

On putting the value we get

`\sf\dashrightarrow \: R\: = \frac{ {10}^(2) * sin(2 * 45) }{10} \\ \\ \sf\dashrightarrow \: R = \frac{100 * sin90 {}^( \circ) } {10} \\ \\ \sf\dashrightarrow \: R \: = (100 * 1)/(10) \\ \\ \sf\dashrightarrow \: R \: = (100)/(10) \\ \\ \sf\dashrightarrow \: R = \cancel (100)/(10) \\ \\ \sf\dashrightarrow \: R = 10m`

So, the range of projectile is 10m.