Question

A 13.5 liter balloon is heated from 248k to 324k. what will it's new volume be?​

Answer 1

The new volume is approximately 17.637 liters

Step-by-step explanation:

The given parameters in the question are;

The initial volume of the gas, V₁ = 13.5 Liter

The initial temperature of the gas, T₁ = 248 K

The new temperature of the gas, T₂ = 324 K

A balloon containing gas that experiences an increase in the temperature of the gas content under constant pressure obeys Charles law which states that the volume of a given mass of gas is directly proportional to its Kelvin temperature is expressed mathematically as follows;

`(V_1)/(T_1) = (V_2)/(T_2)`

Where;

V₁ = The initial volume of the gas

T₁ = The initial temperature of the gas

V₂ = The new volume of the gas

T₂ = The new temperature of the gas

From the question, we have;

V₁ = 13.5 Liter

T₁ = 248 K

T₂ = 324 K

Therefore, we have;

`{V_2}= (V_1)/(T_1) * T_2`

`{V_2}= (324 \ K)/(248 \ K) * 13.5 \ L=17(79)/(124) \ L\approx 17.637 \ L`

The new volume, V₂ ≈ 17.637 L.