Question

1. If 3.2 L of nitrogen monoxide and 4.3 g of oxygen gas are combined, what volume of nitrogen dioxide will be formed? 2NO + 0, -> 2NO,​

Answer 1

`3.2 / 22.4 = (1)/(7) mol \: no`

`4.3 / 32 = 0.134mol \: o2`

Step-by-step explanation:

NO is limit reactant so:

1÷7×46=6.57 grams of NO2 will form