Question

4NH3(g) + 5O2(g) -> 4NO(g) + 6H2O(g)

How many moles of ammonia (NH3) are needed if 2.75 moles of water (H2O) were produced?

4.13 mol

1.83 mol

4 mol

(only respond if you have the answer)

6.8 mol

Answer 1

Answer: from multipliers of substances and real amount of moles you get an equation

For x = amount of ammonia in moles. X/4 = 2.75/6 and x = 11/6 = 1.83 mol

Step-by-step explanation: