Question

How many solutions exist for the given equation?

3X + 13 = 3(x + 6) + 1
O zero
O one
O two
O infinitely many

Answer 1

• 3x + 13 = 3(x + 6) + 1
• 3x + 13 = 3x + 18 + 1
• 3x + 13 = 3x + 18 +1 1
• 3x - 3x = 19 - 13
• 0 = 6
• 0 = 0

There's no x , so no solution will be there therefore:

ans :- zero

All Done!

Answer 2

Hey there!

3x + 13 = 3(x + 6) + 1

3x + 13 = 3(x) + 3(6) + 1

3x + 13 = 3x + 18 + 1

3x + 13 = 3x + 19

SUBTRACT 3x to BOTH SIDES

3x + 13 - 3x = 3x + 19 - 3x

SIMPLIFY IT!
13 = 19

SUBTRACT 13 to BOTH SIDES

13 - 13 = 19 - 13

SIMPLIFY IT!
0 = 6

Thus, this mean that you have NO SOLUTION.

Therefore, your answer is: Zero (Option A.)

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)