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How many grams of O2 are needed to completely burn 69.3g C3H8?
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How many grams of O2 are needed to completely burn 69.3g C3H8?

User Skmasq
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1 Answer

9 votes

Answer:

C3H8 + 5O2 --> 3CO2 +4H2O

no.of moles of C3H8=64.3/(3*12+8) =1.461363636moles

no.of moles of O2=1.461363636*5 =7.306818moles

mass of O2= 7.306818*(16*2)=233.81g

Step-by-step explanation:

User Parze
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