Answer:
Step-by-step explanation:
According to hardyweinberg principle
p+q= 1
P2+2pq+q2=1
given that
Black fur =B =p(dominant allele)
White fur =b =q (recessive allele)
q2=16%
16/100=0.16
q=√0.16
q=0.4
Since p+q=1
P=1-q
P=1-0.4
P=0.6
Therefore the allele frequency for dominant organism Black fur is 0.6