Question

A cement mixer with a radius of 2 m spins with a tangential velocity of 0.4 m/s. Determine the centripetal acceleration of a piece of dried cement stuck to the inside wall of the mixer.

Answer 1

`a=0.08\ m/s^2`

Step-by-step explanation:

Given that,

The radius of the mixer, r = 2 m

Tangential velocity of the mixer, v = 0.4 m/s

We need to find the centripetal acceleration of a piece of dried cement stuck to the inside wall of the mixer. The formula for the centripetal acceleration is given by :

`a=(v^2)/(r)\\\\a=((0.4)^2)/(2)\\\\a=0.08\ m/s^2`

So, the centripetal acceleration is equal to
`0.08\ m/s^2`.