The mean absolute deviation is 2.6
Using the data given for Catapult A :
- 144, 154, 148, 147, 150, 150, 156,151, 153, 151
The mean absolute deviation is :
The mean, μ = (144+154+148+147+150+150+156+151+153+151) / 10 = 150.4
Now we have :
Σ|x - μ| = |144 - 150.4| + |154 - 150.4| +...+ |153 - 150.4| + |151 - 150.4|
Σ|x - μ|= 6.4 + 3.6 +...+ 2.6 + 0.6 = 26
Σ|x - μ|/n = 26/10 = 2.6
Hence, the mean absolute deviation is 2.6