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An engineer is testing two designs for a catapult. She wants the catapult to launch objects 150 feet. The engineer records the distances in feet for 10 trials for the two designs, shown below. Catapult A: 144, 154, 148, 147, 150, 150, 156,151, 153, 151 Calculate the mean absolute deviation for Catapult A.

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6 votes

Answer:

random sample of 10 tomatoes from each farm are shown below in ounces. 4.

Explanation:

User Roman Eremin
by
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2 votes

The mean absolute deviation is 2.6

Using the data given for Catapult A :

  • 144, 154, 148, 147, 150, 150, 156,151, 153, 151

The mean absolute deviation is :

  • ∑|x - μ|/n

The mean, μ = (144+154+148+147+150+150+156+151+153+151) / 10 = 150.4

Now we have :

Σ|x - μ| = |144 - 150.4| + |154 - 150.4| +...+ |153 - 150.4| + |151 - 150.4|

Σ|x - μ|= 6.4 + 3.6 +...+ 2.6 + 0.6 = 26

Σ|x - μ|/n = 26/10 = 2.6

Hence, the mean absolute deviation is 2.6

User OtterFamily
by
8.1k points
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