Question

When 577 J of energy is added to 32.3 g of aluminum at 17.4ºC, the temperature increases to 46.6ºC. What is the specific heat of aluminum?

Answer 1

0.612 J/g°C

Step-by-step explanation:

Using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat (Joules)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C) i.e. final - initial temperature

According to the information provided in this question;

Q = 577 J

m = 32.3 g

c = ?

Final temp = 46.6ºC, initial temp. = 17.4°C

∆T = (46.6 - 17.4) = 29.2°C

Using Q = m × c × ∆T

c = Q ÷ m.∆T

c = 577 ÷ (32.3 × 29.2)

c = 577 ÷ 943.16

c = 0.6117

c = 0.612 J/g°C