Question

HEY PLEASE HELP. The student's savings box had accumulated 35 twenty and fifty cent coins in one month, in the total amount of 10.3 euros. Several 20 and several 50 cent coins are in the box.

Answer 1

Answer: 11 and 24

Explanation:

Given

There are 35- 50 cents and 20 cents coins

The total of them is 10.3 euros

Suppose no of 50 cents coins is x and 20 cents is y

so we can write

`\Rightarrow 0.5x+0.2y=10.3\quad \ldots(i)`

Also,

`\Rightarrow x+y=35\quad \ldots(ii)`

Solving (i) and (ii) we get

`x=11; y=24`

There are 11 fifty cent and 24 twenty cents coins