Question

A man who is 2m tall stands on horizontal ground 30m from a tree. The Angel of elevation of the top of the tree from his eyes is 28 . Fine the distance between the men eyes to the top of the tree

Answer 1

Answer:33.95 m

Explanation:

Given

The height of the man is 2 m

Distance between man and tree is 30 m

the angle of elevation of the top from the eyes is
`28^(\circ)`

from the figure,

`\Rightarrow \tan 28^(\circ)=(h)/(30)\\\\\Rightarrow h=30\tan 28^(\circ)=15.91\ m`

Using Pythagoras we can write

`\Rightarrow AD^2=ED^2+AE^2\\\Rightarrow AD^2=30^2+15.91^2\\\Rightarrow AD=33.95\ m`

Thus the distance between the men eyes to the top of the tree is 33.95 m