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11. What is the area of a rectangle whose length (2x+5) cm and width (x-1) cm?

c. 2x2 - 3x + 5 cm?
d. 2x² + 3x - 5 cm?
a 2x2 + 3x + 5 cm?
b. 2x? - 3x - 5 cm?
12. If the area of a square is (2x - 3)- sq. units, then the measure of one side
is:
a. 2x -3 units
C. 3x - 2 units
b. 3x units
d. 2x units
13. The product of two numbers is (4y2 -1). If one of the numbers is (2y + 1).
what is the other number?
a. (2y + 1) b. (2y - 1)
C. (4y + 1)
d. (4y - 1)
14. Which special product is represented by: (5a? - 7b)??
a. Product of Two Binomials
c. Cube of a Binomial
b. Square of a Binomial
d. Product of a Binomial and a Trinomial​

User Alok Singh
by
6.4k points

1 Answer

0 votes

Answer:


A=2x^2+3x-5

Explanation:

Given that,

Length = (2x+5) cm

Width = (x-1) cm

We need to find the area of a rectangle. The formula for the area of rectangle is given by :

A = lb


A=(2x+5)(x-1)\\\\=2x^2-2x+5x-5\\\\=2x^2+3x-5

So, the required area is equal to
2x^2+3x-5.

User OnIIcE
by
6.0k points
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