Question

A trapeze artist swings in simple harmonic motion with a period of 3.8 s.

Calculate the length of the cables supporting the trapeze. (g=9.81 m/s2)

Answer 1

As we know that time period of simple pendulum is given as

T = 2π √L/g

here we know that

T = 3.8 s

now from above equation we know that

T² = 4π² (L/g)

now on rearranging the above equation we will have

L = gT² / 4π²

now plug in all data into it

L = (9.8) (3.8)² / (4) (3.14)²

so the length of the cable must be 3.6 m