Question

A balloon rubbed against a pair of jeans gains a charge of -6x10^-6 C. If the balloon is moved to a distance of 0.25 m away from the jeans, what is the size and direction of the electric force between the balloon and jeans ?

Answer 1

Answer: 5.184 N

Step-by-step explanation:

Given

The charge on the balloon is
`q_1=-6* 10^(-6)\ C`

distance between balloon and jeans is
`r=0.25\ m`

After rubbing jeans must acquire the same opposite charge i.e.

`q_2=6* 10^(-6)\ C`

The electrostatic force between them

`\Rightarrow F=(kq_1q_2)/(r^2)\\\\\Rightarrow F=(9* 10^9* 6* 10^(-6)* 6* 10^(-6))/(0.25^2)\\\\ \Rightarrow F=4* 4* 9* 36* 10^(-3)=5.184\ N`

nature of force will be attractive i.e. Jeans will try to pull the balloon