Question

A body of mass 250g is release d from the top of a building. If the body hits the ground with a velocity of 4m/s, calculate the height of the building (g = 10 m/s squared)​

Answer 1

the height of the building is 0.8 m.

Step-by-step explanation:

Given;

mass of the object, m = 250 g = 0.25 kg

final velocity of the object, v = 4 m/s

let the height of the building = h

Apply the principle of conservation of energy to determine the height of the building;

¹/₂mv² = mgh

¹/₂v² = gh

`h = (v^2)/(2g) \\\\h = (4 ^2)/(2 * 10) \\\\h = 0.8 \ m`

Therefore, the height of the building is 0.8 m.