Question

If m = (3x-1) and n = (3x+1),sjow that x² = mn+1 by 9​

Answer 1

See proof below

Explanation:

Given that m = (3x-1) and n = (3x+1)

Taking the product

mn = (3x-1)(3x+1)

mn = 9x^2+3x-3x-1

mn = 9x^2 - 1

mn+1 = (9x^2-1+1)

mn+1 = 9x^2

Dividing both sides by 9

(mn+1)/9 = (9x^2)/9

(mn+1)/9 = x^2

Swap

x^2 = (mn+1)/9

This shows the required proof