Answer:
The function that can be used to describe the number (n) of bacteria after 2 minutes is;
![P = 4 \cdot e^{\left((ln(32))/(5) * 2\right)} \approx 4 \cdot e^(\left(0.693* 2\right))](https://img.qammunity.org/2022/formulas/mathematics/high-school/vobxqnh00taj3c6ivbhvpiwli8kire8l9j.png)
Explanation:
The data in the table are presented as follows;
Number of bacteria; 4, 128, 4,096, 131,072
Number of minutes from initial state; 0, 5, 10, 15
The general equation for population growth is presented as follows;
![P = P_0 \cdot e^(r\cdot t)](https://img.qammunity.org/2022/formulas/mathematics/high-school/b54r93sdj2emsymkm6hhg5adm6gqookqy4.png)
Where;
P = The population after 't' minutes
P₀ = The initial population
r = The population growth rate
t = The time taken for the growth in population numbers
At t = minutes. we have;
![4 = P_0 \cdot e^(r*0) = P_0](https://img.qammunity.org/2022/formulas/mathematics/high-school/9lw45gh4uzxfqcily65rxywte8w0h76gue.png)
∴ P₀ = 4
At t = 5, we have;
![128 = 4 \cdot e^(r* 5)](https://img.qammunity.org/2022/formulas/mathematics/high-school/148qrtc589cfc991lxq82ppgi501xzxbzm.png)
![\therefore e^(r* 5) = (128)/(4) = 32](https://img.qammunity.org/2022/formulas/mathematics/high-school/3kkxq6m3arc2sgct428ifkbdsk0hzju241.png)
![ln\left(e^(r* 5)\right) = ln(32)](https://img.qammunity.org/2022/formulas/mathematics/high-school/kntndz2jr5kvkgk74ji4ffkb6vu6hjjuyw.png)
∴ r × 5 = ㏑(32)
r = ln(32)/5 ≈ 0.693
The number (n) of bacteria after 2 minutes is therefore;
![P = 4 \cdot e^{\left((ln(32))/(5) * 2\right)} \approx 4 \cdot e^(\left(0.693* 2\right))](https://img.qammunity.org/2022/formulas/mathematics/high-school/vobxqnh00taj3c6ivbhvpiwli8kire8l9j.png)