Question

1 point

1. A balloon has 1.55 L of air in it exerting a pressure of 105.2 kPa. At

constant temperature, if the pressure increases to 122.0 kPa, what is the

volume?

Answer 1

`V_2=1.34L`

Step-by-step explanation:

Hello there!

In this case, since this problem is describing how pressure changes as a function of volume and vice versa, it is possible recall the Boyle's law as shown below:

`P_1V_1=P_2V_2`

Whereas we are asked to compute the volume when the change is pressure is performed (V₂); thus, we proceed as follows:

`V_2=(P_1V_1)/(P_2)\\\\V_2=(1.55L*105.2kPa)/(122.0kPa)\\\\V_2=1.34L`

Best regards!