Answer:
Step-by-step explanation:
The missing part of the question is attached in the diagram below, the second diagram shows the schematic view of the stress-strain curve and the plane stress.
From the given information:
The elastic modulus is:

Hence, suppose 0.2% offset cuts the stress-strain curve at a designated point A from the image attached below, then the yield strength relating to the stress axis from the curve will be
= 270 MPa.
The shear yield strength by using von Mises criteria is estimated as;

The shear yield strength by using Tresca criteria is:
