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The length rectangle is 7.1 cm and it's breadth is 2.5 cm. Find area and perimeter.​

2 Answers

8 votes

Question :


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The length rectangle is 7.1 cm and it's breadth is 2.5 cm. Find area and perimeter.


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Given:


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Length of rectangle = 7.1 cm

Breadth of rectangle = 2.5 cm


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To find:


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Area of rectangle

Perimeter of rectangle


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Solution:


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Part 1 :‐

To find area of rectangle


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we know:

Area of rectangle = Length × Breadth


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So:-

↣Area of rectangle = Length × Breadth


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↣Area of rectangle = 7.1 × 2.5 (cm × cm)


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↣Area of rectangle = 7.1 × 2.5 cm²


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↣Area of rectangle =( 71 × 25 )/100cm²


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↣Area of rectangle =( 71 × 25 )/(25 × 4)cm²


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↣Area of rectangle =( 71 × 1)/(1 × 4)cm²


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↣Area of rectangle = 71/4cm²


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↣Area of rectangle = 17.75 cm²


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Part 2 :‐

Part 2 :‐To find perimeter of rectangle


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we know:

Perimeter of rectangle =2( Length + Breadth )


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So:-


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↣Perimeter of rectangle =2( Length + Breadth )


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↣Perimeter of rectangle =2( 7.1 + 2.5 )cm


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↣Perimeter of rectangle =2( 9.6) cm


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↣Perimeter of rectangle =2 × 9.6 cm


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↣Perimeter of rectangle = 19.6 cm


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✎ᝰ Cheers! all done :)

User Sachin Vas
by
7.1k points
8 votes

Answer:

  • Area = 17.75 cm²

  • Perimeter = 19.2 cm

Explanation:

In the question we're given ,

  • Length of rectangle = 7.1 cm

  • Breadth of rectangle = 2.5 cm

And we are asked to find ,

  • Area of rectangle

  • Perimeter of rectangle

Finding Area :

We know that ,


\longmapsto \: \pink{\boxed{\sf{Area \: of \: rectangle = l * b}}}

Where ,

  • l = length of rectangle

  • b = breadth of rectangle

So substituting values :


\hookrightarrow \: 7.1 * 2.5

Multiplying 7.1 and 2.5 :


\hookrightarrow \: \blue{\boxed{ \bold{17.75 \: cm {}^(2) }}}

  • Therefore , area of rectangle is 17.75 cm²

Finding Perimeter :

We know that ,


\longmapsto \: \pink{\boxed{ \sf{Perimeter \: of \: rectangle = 2 ( l + b )}}}

Where ,

  • l = length of rectangle

  • b = breadth of rectangle

So substituting values :


\hookrightarrow \: 2(7.1 + 2.5)

Solving parenthesis by adding 7.1 and 2.5 :


\hookrightarrow \: 2(9.6)

Multiplying 2 and 9.6 :


\hookrightarrow \: \blue{\boxed{\bold{19.2 \: cm}}}

  • Therefore , perimeter of rectangle is 19.2 cm

#Keep Learning

User IHowell
by
6.4k points