Question

The length rectangle is 7.1 cm and it's breadth is 2.5 cm. Find area and perimeter.​

Answer 1

❖Question :

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The length rectangle is 7.1 cm and it's breadth is 2.5 cm. Find area and perimeter.

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❖Given:

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Length of rectangle = 7.1 cm

Breadth of rectangle = 2.5 cm

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❖ To find:

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Area of rectangle

Perimeter of rectangle

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❖ Solution:

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Part 1 :‐

To find area of rectangle

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we know:

Area of rectangle = Length × Breadth

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So:-

↣Area of rectangle = Length × Breadth

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↣Area of rectangle = 7.1 × 2.5 (cm × cm)

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↣Area of rectangle = 7.1 × 2.5 cm²

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↣Area of rectangle =( 71 × 25 )/100cm²

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↣Area of rectangle =( 71 × 25 )/(25 × 4)cm²

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↣Area of rectangle =( 71 × 1)/(1 × 4)cm²

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↣Area of rectangle = 71/4cm²

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↣Area of rectangle = 17.75 cm²

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Part 2 :‐

Part 2 :‐To find perimeter of rectangle

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we know:

Perimeter of rectangle =2( Length + Breadth )

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So:-

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↣Perimeter of rectangle =2( Length + Breadth )

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↣Perimeter of rectangle =2( 7.1 + 2.5 )cm

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↣Perimeter of rectangle =2( 9.6) cm

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↣Perimeter of rectangle =2 × 9.6 cm

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↣Perimeter of rectangle = 19.6 cm

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✎ᝰ Cheers! all done :)

Answer 2

• Area = 17.75 cm²

• Perimeter = 19.2 cm

Explanation:

In the question we're given ,

• Length of rectangle = 7.1 cm

• Breadth of rectangle = 2.5 cm

And we are asked to find ,

• Area of rectangle

• Perimeter of rectangle

✰ Finding Area :

We know that ,

`\longmapsto \: \pink{\boxed{\sf{Area \: of \: rectangle = l * b}}}`

Where ,

• l = length of rectangle

• b = breadth of rectangle

So substituting values :

`\hookrightarrow \: 7.1 * 2.5`

Multiplying 7.1 and 2.5 :

`\hookrightarrow \: \blue{\boxed{ \bold{17.75 \: cm {}^(2) }}}`

• Therefore , area of rectangle is 17.75 cm²

✰ Finding Perimeter :

We know that ,

`\longmapsto \: \pink{\boxed{ \sf{Perimeter \: of \: rectangle = 2 ( l + b )}}}`

Where ,

• l = length of rectangle

• b = breadth of rectangle

So substituting values :

`\hookrightarrow \: 2(7.1 + 2.5)`

Solving parenthesis by adding 7.1 and 2.5 :

`\hookrightarrow \: 2(9.6)`

Multiplying 2 and 9.6 :

`\hookrightarrow \: \blue{\boxed{\bold{19.2 \: cm}}}`

• Therefore , perimeter of rectangle is 19.2 cm

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