![\large{|\underline{\mathtt{\red{G}\blue{i}\orange{v}\pink{e}\blue{n}\purple{}\green{}\red{↯}\blue{}\orange{}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/9b2e40sxohod7z7ngcs1q8gm3emfasb8ql.png)
- Area of triangle = 6 3/8 yards²
- Height of triangle = 2 1/2 yards
![\large{|\underline{\mathtt{\red{T}\blue{o}\orange{\:}\pink{F}\blue{i}\purple{n}\green{d}\red{↯}\blue{}\orange{}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/8vtrfoik4u5tzeqxyxl2qt8xeln4ggon1q.png)
![\large\underline{\underline{\maltese{\blue{\pmb{\sf{\: Explanation :-}}}}}}](https://img.qammunity.org/2023/formulas/mathematics/college/3qqamak0f6opykuuexm7wfjhf8fvan3ftu.png)
![\boxed{\mathfrak{area = (1)/(2) * base * height}}](https://img.qammunity.org/2023/formulas/mathematics/college/fiech9rvuzbty65zoyhsbnikixzymk9qcp.png)
We are already given the values, Let's plug them and solve for x i.e base
![\bf\: 6 (3)/(8) = (1)/( \cancel2) * x * \cancel2 (1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/e1u8l6ky0lj2skwau4pid0jht6hbd97684.png)
![\bf \: 6(3)/(8) = x * (1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/8vvcan82d85zcc74i3dx26jxed3pud3m81.png)
Convert the mixed number to an improper fraction
![\bf \: (51)/(8) = (1)/(2) x](https://img.qammunity.org/2023/formulas/mathematics/college/tt8vrxqwo3bmanle98eh4on26vjauueh7x.png)
Multiply both sides of the equation by 2
![\boxed{ \tt \: x = (51)/(4) }](https://img.qammunity.org/2023/formulas/mathematics/college/aalpdwy2ewmutn6mnsig360yr520e91x9e.png)
➪ Therefore, The base of the triangle is 51/4 yards...~