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Practice: A gas reaction is allowed to take place in a canister while submerged in water at a temperature of 25oC. The gas expands and does P-V work on the surroundings equal to 385 J. At the same time, the temperature of the water decreases to 20oC as the energy in the gas reaction reaches 364 J. What is the change in energy of the system

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Answer:

change in energy of the system = - 21 J

Step-by-step explanation:

Δu = q + w

q = 364 J

w = - 385

Temperature of system drops from 25°c to 20°c

hence

Δu ( change in energy ) = q - w

= 364 - 385

= -21 J

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