Answer:
![Area = 40 ( 84)+ 2 *(294)](https://img.qammunity.org/2022/formulas/mathematics/middle-school/cqrm13wtrufdfn8untlp6k0cipl91t4688.png)
Explanation:
There is only one figure in the attached image and the solution (surface area) is as follows:
The shape can be sub-divided into:
1. Rectangle
Dimension: 40 by 35
2. Rectangle
Dimension: 40 by 28
3. Rectangle
Dimension: 21 by 40
4. 2 triangles
Base: 21 and Height: 28
Calculate area of each and add them up to get the surface area of the figure.
1. Rectangle
Dimension: 40 by 35
![A_1 = 40 * 35](https://img.qammunity.org/2022/formulas/mathematics/middle-school/43fucz1dzmejv32jnk23x6knvhuorufqke.png)
2. Rectangle
Dimension: 40 by 28
![A_2 = 40 * 28](https://img.qammunity.org/2022/formulas/mathematics/middle-school/967cg2izx4za02aun7q3f578qwiflb8ysh.png)
3. Rectangle
Dimension: 21 by 40
![A_3 = 40 * 21](https://img.qammunity.org/2022/formulas/mathematics/middle-school/icxl4vgf5838jaetnesk0zvmc69adh1mhi.png)
4. 2 triangles
Base: 21 and Height: 28
![A_4 = 2 * (1)/(2) * 21 * 28](https://img.qammunity.org/2022/formulas/mathematics/middle-school/jplkl8c37el3b4hitfm9pqvsqkr2ki8jv3.png)
So, the area is:
![Area = A_1 +...+A_4](https://img.qammunity.org/2022/formulas/mathematics/middle-school/n32x0r7g2m4b8sy4j6qr9ref9zocx5u0oc.png)
![Area = 40 * 35 + 40 * 28 +40 * 21 + 2 * (1)/(2) * 21 * 28](https://img.qammunity.org/2022/formulas/mathematics/middle-school/mpynkpms3zpr5v1uoxz1dmz10gr2tvu3de.png)
Factor out 40
![Area = 40 ( 35 + 28 + 21 )+ 2 * (1)/(2) * 21 * 28](https://img.qammunity.org/2022/formulas/mathematics/middle-school/3sotem7uyzm3w6a8a3rde7vex6id4sekrp.png)
![Area = 40 ( 84)+ 2 * (1)/(2) * 21 * 28](https://img.qammunity.org/2022/formulas/mathematics/middle-school/t1ol3qw63wqtk9s2hb8tnynf295xzhol5x.png)
![Area = 40 ( 84)+ 2 *(294)](https://img.qammunity.org/2022/formulas/mathematics/middle-school/cqrm13wtrufdfn8untlp6k0cipl91t4688.png)