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In AJKL, solve for x.

In AJKL, solve for x.-example-1

1 Answer

4 votes

Answer:

x ≈ 66.73

Explanation:

Using the tangent ratio in the right triangle

tan27° =
(opposite)/(adjacent) =
(KL)/(JK) =
(34)/(x) ( multiply both sides by x )

x × tan27° = 34 ( divide both sides by tan27° )

x =
(34)/(tan27) ≈ 66.73 ( to 2 dec. places )

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