Question

Based on the chemical reaction below, if you produce 109.34 moles of Na, how

many g of Cl2 were produced? 2NaCl (s) -> 2Na(s) + Cl2(g) *

Answer 1

Answer: 3881 g of
`Cl_2` will be produced along with 109.34 moles of Na

Step-by-step explanation:

The balanced chemical equation is:

`2NaCl(s)\rightarrow 2Na(s)+Cl_2(g)`

According to stoichiometry :

2 moles of
`Na` are produced along with = 1 mole of
`Cl_2`

Thus 109.34 moles of
`Na` will produced along with=
`(1)/(2)* 109.34=54.67moles` of
`Cl_2`

Mass of
`Cl_2=moles* {\text {Molar mass}}=54.67moles* 71g/mol=3881g`

Thus 3881 g of
`Cl_2` will be produced along with 109.34 moles of Na