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How many moles are occupied by 2.2x10^23 particles of copper?

User Sowrov
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1 Answer

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22 votes

Answer:

Step-by-step explanation:

1mole of copper = 6.02 * 10^23 particles of copper

x mol of copper =2.2 * 10^23 particles

This is a proportion. All you need do is solve using the rules of proportions.

1/x = 6.02 * 10^23/2.2 * 10^23 Cross multiply

6.02 * 10^23x = 1* 2.2*10^23 Divide by 6.02 * 10^23

x = 2.2*10^23 / 6.02* 10^23

x = .365 mols of copper

User Violeta Georgieva
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