Question

Find the equation of a line with slope -2 that contains the point (-3,3). O y = -2x +3 O y = -2x - 3 O y = -3x-2 O y=-3x - 6​

Answer 1

Note that:

• Given point: (-3,3)
• Slope = -2
• Formula of point slope form: y - y₁ = m(x - x₁)

Substitute the value to find the equation of the line.

• y - y₁ = -2(x - x₁)
• => y - 3 = -2{x - (-3)}
• => y - 3 = -2{x + 3}
• => y - 3 = -2x - 6
• => y = -2x - 3

Option B is correct.

Answer 2

y = -3x-2

Solution :

Formula of point slope form: y - y₁ = m(x -x₁)

Given point: (-3,3)

Slope: -2

Lets, find the equation of the line:

y - y₁= -2(x -x₁)

→y-3 = -2[x - (-3)]

→y - 3 = -2[x + 3]

→y - 3 = -2x - 6

→y = -2x - 3