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g A wheel of radius 1.2 meters initially rotates clockwise around its center with an angular speed of 10 rad/s, and it steadily increases its rate of rotation. 4 second later, the rate of rotation is 30 rad/s. What is the ratio of the angular acceleration of a point on the rim of the wheel to a point that is 0.6 meters from the center of the wheel?

1 Answer

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Answer:

α = 5 rad / s²

Step-by-step explanation:

This is a rotational kinematics exercise.

They indicate the initial velocity wo = 10 rad / s

w = w₀ + α t

α =
(w-w_o )/(t)

let's calculate

α =
(30-10)/(4)

α = 5 rad / s²

The velocity, the angular relation are the same in all the points of the wheel, the velocities and linear accelerations are the ones that change

a = α r

v = w r

User Tomq
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