What is the pH of 2.88*10^-5 M LiOH?

asked Feb 11, 2022 217k views

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Answer: 9.46

Explanation: in LiOH solution concentration of OH- ions is 2.88·10^-5 M

And pOH = -log( 2.88·10^-5 M) = 4.54. Because PH + pOH = 14.00

Then pH = 14-4.54

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