Question

A spring of constant 10 N/m is oscillating a mass of 1kg. What is the period of oscillation?
a

Answer 1

Hi there!

We can use the following equation for the period of an oscillating spring system:

`\large\boxed{T = 2\pi \sqrt{(m)/(k)}}`

`T` = Period (s)

`m` = mass (kg)

`k` = Spring Constant (N/m)

Plug in the givens and solve.

`T = 2\pi \sqrt{(1)/(10)} = \boxed{1.987 s}`