Explanation:
I'll do 2.
Alright,Alex let say we have factored a quadratic into two binomial, for example
![(5x + 3)(6x - 4)](https://img.qammunity.org/2022/formulas/mathematics/high-school/mn09pi1qihhln8de4t7umvvnad11zjytau.png)
If we set both of those equal to zero
![(5x + 3)(6x + 4) = 0](https://img.qammunity.org/2022/formulas/mathematics/high-school/5ro45sto7i1faycmfgf6hgyiip0pt87y0p.png)
We can used the zero product property in this case to find the roots of the quadratic equation.
This means that
![if \: ab = 0 \: then \: a = 0 \: and \: b = 0](https://img.qammunity.org/2022/formulas/mathematics/high-school/zgshf0x9lnxtlbp5gsos1ji0asp7lx8hv9.png)
This means we set each binomal equal to zero to find it root.
![5x + 3 = 0](https://img.qammunity.org/2022/formulas/mathematics/high-school/boo53tcxhdime0n5yeuvvcj6ql5qp1kxtf.png)
![5x = - 3](https://img.qammunity.org/2022/formulas/mathematics/high-school/iof5pmily81q10m5ke3lvkc3ecih9qawpt.png)
![x = - (3)/(5)](https://img.qammunity.org/2022/formulas/mathematics/high-school/kyhau6zv5pe1rxzj4hl1bsfrgmynidnzj1.png)
![6x + 4 = 0](https://img.qammunity.org/2022/formulas/mathematics/high-school/ytnawbcro1cylajdgoqmazjevd3bf7yuyb.png)
![6x = - 4](https://img.qammunity.org/2022/formulas/mathematics/high-school/fy7cfxmn6gn2mkq522b2pbyheaws2yl73p.png)
![x = - (2)/(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/hq6j13rw3t3734y8214598t3kvmnk3oqqa.png)
So our roots are negative 3/5 and negative 2/3 using zero product property